The only successful outcome in this bet is that the first game is a home victory and the second game is an away victory, HA. This is one of 9 possible outcomes. The probability for this bet to turn out correct will thus be one out of nine. The probability for the event A to happen is the number of successes divided by the number of possible outcomes:
We have observed that the number of possible combination we can bet when we bet on two soccer games is 9 combinations (Take a look at this tree-diagram). We can also consider the two games to be two independent choices, n1 and n2. In this case both choices (the games) have three outcomes (home victory, draw or away victory).
Number of possible outcomes when we bet on three games: Number of possible outcomes when we bet on 12 games:
This way to find the total number of outcomes is called the multiplication prinsipal If we bet on only one option in every game the probability of betting 12 games correctly will be:
What is the probability that the dice shows three eyes. A couple decides to get two children. In this exercise we assume that the probability of giving birth to a boy is equal to the probability of giving birth to a girl. Let us toss two coins. b) What is the probability that one coin shows head and the other one shows tail? |
